Ukuphakama iphiramidi. Njani ukuze ayifumane?

Iphiramidi - emacala, noseko yayo buyimilo. Bonke ubuso kwifomu jika oonxantathu ezihlangabezana kwi enekona enye. Iiphiramidi ke ezibunxantathu, Ikwadrilatherali njalo njalo. Ukuze ukuqonda oko iphiramidi phambi kwakho, kwanele ukuba zibale inani engile kwi kwisiseko sayo. Inkcazo "ukuphakama iphiramidi 'ukuxhaphaka kakhulu geometry kwiinjongo zekharityhulam. Eli nqaku liza kuzama ukuba siqwalasele iindlela ezahlukeneyo abayifumanayo.

iindawo ezilandelanayo

iphiramidi nganye iqulathe ezi zinto zilandelayo:

• ubuso ongekhe babe engile ezintathu kwaye idibane kwindawo enekona;
• apothem imele ekuphakameni wehlela ukusuka phezulu kwayo;
• phezulu iphiramidi - ingongoma lebhokisi emiphethweni osecaleni, kodwa oku akuthethi kulala moya koseko;
• base - buyimilo, nto leyo asisiso kwincam;
• ukuphakama bephiramidi icandelo osibonayo umphezulu iphiramidi, noseko lwalo yakha esinekona sasekunene.

Indlela yokufumana kubude yephiramidi, ukuba uyazi umthamo wayo

Emva ifomula iphiramidi volume V = (S * h) / 3 (kwi-V ifomula - volume, S - indawo isisekelo, h - ubude iphiramidi), sifumanisa ukuba h = (3 * V) / S. Ukuqinisa eziphathekayo, makhe ukusombulula ingxaki ngoko nangoko. Elingunxantathu Iphiramidi square iziseko yi-50 cm ^2, xa umthamo walo 125 cm ^3. ukuphakama Unknown yephiramidi olunxantathu, kwaye kufuneka ukuba ukufumana. Yinto elula: ukufaka idatha ifomula yethu. Thina ukufumana h = (3 * 125) / 50 = 7.5 cm.

Indlela yokufumana kubude yephiramidi, ukuba siyazi ubude idiagonal kunye nokuphela kwegqabi yayo

Njengoko khumbula, ukuphakama sephiramidi yenza kunye nesiseko engile yayo elungileyo. Oku kuthetha ukuba ukuphakama ubambo kunye nesiqingatha kwikonw ngekona kunye zenze unxantathu lasekunene-engile egqithe. Abaninzi, Kakade ke, khumbula theorem kaPythagoras. Ukwazi imilinganiselo emibini, ixabiso lesithathu kuya kuba lula ukufumana. Khumbula eyaziwa theorem a² = b² + c², emasikwini - le hypotenuse, kwaye kule meko ngohlangothi yephiramidi; b - lokuqala umlenze okanye isiqingatha oxwesileyo kunye - ngokulandelelana, le yesibini umlenze okanye ukuphakama iphiramidi. Ukususela kule c² formula = a² - b².

Ngoku ingxaki: kwi idiagonal lasekunene bephiramidi-20 cm, lo gama ubude ngohlangothi - 30 ukuphakama cm kufuneka kufunyanwe .. Sombulula: c² = 30² - 20² = 900-400 = 500 Ngenxa yoko, = √ 500 = malunga 22.4.

Indlela yokufumana ubude yephiramidi thumbanails

It is a yepholigoni, nto leyo iba icandelo onxusene kwisiseko sayo. Ukuphakama yephiramidi thumbanails - icandelo esithungelanayo ezimbini ekusungulweni yayo. Ukuphakama inokufumaneka iphiramidi rhoqo, uya kwaziwa ukuba ebudeni idayagonali zeenqwelwana amabini, kwaye kananjalo ngohlangothi iphiramidi. Vumela isiseko enkulu oxwesileyo elingana D1, ngoxa isiseko ezincinane oxwesileyo - D2, kwaye oluphezulu ubude - l. Ukuze ufumane ukuphakama kuba ekuphakameni malunga aphezulu iingongoma ezimbini umzobo ephantsi kwi kwisiseko sayo. Sibona into siyifumene oonxantathu ezimbini ekunene, ukuba uhlala ukufumana ubude imilenze. Kuba oku idiagonal enkulu of a Khupha ezincinane kwaye silahlule nge 2. Ekubeni ngomlenze omnye sifumana: a = (D1-D2) / 2. Emva koko, ngokutsho theorem kaPythagoras, sinokufumanisa kuphela umlenze yesibini, nto leyo ukuphakama iphiramidi.

Ngoku jonga lonke ityala xa befundisa. Lo msebenzi phambi kwethu. Iphiramidi thumbanails uye isikwere apha emazantsi, isiseko esikhulu ubude oxwesileyo yi-10 cm, kanti ezincane - 6 cm, kwaye fin ilingana cm 4 ngobude kufuneka ukufumana .. Ukuze ufumane isiqalo ngomlenze omnye a = (10-6) / 2 = 2 cm omnye umlenze ulingana no-2 cm, kwaye hypotenuse - 4 cm Icacili phandle ukuba yesibini umlenze okanye ukuphakama iya kulingana 16-4 = 12, ngamanye h = .. √12 = zimalunga nesi-3.5 cm.