Imisebenzi malunga indawo yembutho, yaye ngaphezulu

Le isimanga isikwere aqhelekileyo. Oku macala malunga axis yaso wayisa kwikonw ngekona ngokusebenzisa embindini kunye namacala. Ukufuna indawo ethile isikwere okanye umthamo ngokubanzi ayikho nzima kakhulu. Ingakumbi Ukuba kwakusazeka ubude icala.

A amagama ambalwa malunga mzobo kunye neempawu zayo

Iimpawu ezimbini zokuqala sizibandakanya nkcazelo. Onke amacala mzobo ayalingana omnye komnye. Ngapha koko, isikwere - oku uxande ekunene. Kwaye ukuba onke amaqela bayalingana kunye engile zibaluleke ngokulinganayo, oko kukuthi, - 90. Lo mhlaba yesibini.

Eyesithathu into enxulumene ubude idayagonali. Nabo, kakhulu, ayalingana omnye komnye. Kwaye yabanikazi kwi engile tye phakathi amanqaku.

Ifomula esetyenziselwa kuphela ubude ecaleni

Okokuqala, phezu isiqu. Ngokuba ubude icala athatyathiweyo ukukhetha unobumba "a." Emva koko, indawo square ibalwa wokubala: S = ^a-2.

Oku ngokulula efunyenwe enye eyaziwa ngokuba uxande. Kulo ubude nobubanzi banda. Square, ezi zinto emibini iyalingana. Ngoko ke, le ndlela kubonakala ixabiso square.

Ifomula, apho ubude oxwesileyo kwakukhona

Yeyona hypotenuse kanxantathu ogama macala imilenze mzobo. Ngoko ke, singakwazi ukusebenzisa theorem quadratic kaPythagoras kunye neziphumo, apho icala kubonakaliswa idiagonal.

Ukuba utshintshwano elula, sifumanisa ukuba lo mmandla lwe ngcambu ngenxa oxwesileyo ibalwa le ndlela ilandelayo:

S = d ^2/2. Apha incwadi d ibonisa idiagonal kwisikwere.

kujikelezo kwifomula

Kwimeko enjalo kuyimfuneko kukubonakalisa icala ngokusebenzisa iperimitha endaweni yaso kungena ifomula ndawo. Ekubeni kwicala efanayo kulo mzobo ezine, iiperimeter kuya kufuneka ukuba kwahlulwa ngo 4. Oku kuya kuba ixabiso esandleni, ezinokukwazi endaweni kungena lokuqala ubale ummandla isikwere.

Ifomula ngokubanzi ngolu hlobo lulandelayo: S = (P / 4) ^2.

Imingeni ukuba izibalo

Inani 1. Kukho isikwere. Isibalo macala omabini ilingana no-12 cm. Bala ummandla isikwere kunye kwebala yayo.

Isigqibo. Ngokuba banikwe sum of emacaleni aso omabini, kuyimfuneko ukwazi ubude omnye. Ekubeni ukwanguwe, inani elithile kufuneka nje ukuba zibe. Okt icala nani 6 cm.

Ke ubude yaye ummandla lowo ungenziwa lula abalwe kusetyenziswa ifomula. Okokuqala-24 cm, kwaye eyesibini - 36 cm ^2.

Phendula. Kujikelezo isikwere yi-24 cm, yaye indawo yayo - 36 cm ^2.

Inani 2. Fumanisa kwindawo isikwere esine obungama-32 mm.

Isigqibo. Ngokulula kufakwe ixabiso umjikelezo kwifomula ebhaliweyo ngasentla. Nangona uyakwazi ukufunda icala lokuqala yembutho, uze kuphela indawo yayo.

Kuzo zombini ezi meko, izenzo ziya kuhamba division yokuqala uze exponentiation. izibalo elula kukhokelela ekubeni lo mmandla imelwe sikwere 64 mm ^2.

Phendula. Le ndawo sokuzingela 64 mm ^2.

3. inani le sigcawu 4 DM. Le uxande ubukhulu: 2 no-6 DM. Apho kula manani mabini indawo enkulu? Zingaphi?

Isigqibo. Ngamana icala isikwere ziya kumakishwa kunye ezinonobumba ua _1, ngoko ke ubude kunye nobubanzi uxande _{no-2 no-2.} Ukuze ubone indawo ngesikwere njengoko ixabiso ₁ Kucingelwa ukuba inxaki, uxande kunye - phinda _i-2 kunye _2. Kulula.

Kubonakala ukuba le ndawo sigcawu 16 DM ^2, kunye uxande - 12 DM ^2. Ngokucacileyo, inani lokuqala mkhulu kuneyesibini. Oku nangona ukuba indawo ngokulinganayo, oko kukuthi, kufuneka lokubiyela efanayo. Ukujonga, unako ukubala lokubiyela. Icala square kufuneka liphindaphindwe 4, ufumana DM 16. Xa uxande esongiweyo ngapha phinda-phinda 2. Kuya kuba inani elifanayo.

Ingxaki kukuba aphendule kodwa zingaphi kwiindawo ezahlukileyo. Ukuba eli nani sisuswe elikhulu kangako. Umahluko ilingana 4 DM ^2.

Phendula. Isikwere 16 ^dm2 12 DM ^2. I sigcawu ngaphezulu kwe-4 DM ^2.

Umceli-mngeni isiqinisekiso

Isimo. On catheters isosceles unxantathu ekunene yakhiwe square. Its wakha indawo hypotenuse apho omnye square yakhiwe. Bonisa ukuba indawo lokuqala kabini ezinkulu kuno yokugqibela.

Isigqibo. Thina bangangenisa nobhalo. Makhe umlenze lowo, ukuphakama ingqalelo hypotenuse, x. Ummandla wesikwere - S _1, okwesibini - _2.

Le ndawo isikwere eyakhelwe phezu catheters sibalwa nje. Kuyinto ulingana ^a-2. Ixabiso yesibini asinto ilula kakhulu.

Okokuqala kufuneka wazi ubude hypotenuse. Le formula ezisebenzisekayo zokusetyenziswa le theorem kaPythagoras. utshintshwano Simple kukhokelela ibinzana ilandelayo: a√2.

Ekubeni nokuphakama unxantathu alinganayo itsalelwa kwi siseko, nayo median kunye nokuphakama, iluthe unxantathu omkhulu zibe isosceles ezimbini ngokulinganayo unxantathu ekunene. Ngoko ke, ukuphakama ilingana isiqingatha hypotenuse. Oko kukuthi, x = (a√2) / 2. Ngenxa yoko kulula ukwazi indawo S _2. Kufumaniseke ukuba ^2/2.

Kuyabonakala ukuba amaxabiso abhalwe zahluke ngqo kabini. Kwaye ixesha lesibini eli nani lingaphantsi. QED.

An umdlalo puzzle ongaqhelekanga - iTangram

Yenziwe lwe ngcambu. Kufuneka zisekelwe kwimigaqo ethile isikwe iimilo ezahlukeneyo. Onke amalungu kufuneka ibe 7.

Baya kuthi lo mdlalo uya kusebenzisa zonke wafumana izinto. Lomakhwenkwe ayakudinga ukuba ezinye iimilo zejiyometri. Umzekelo, uxande, trapezoid okanye parallelogram.

Kodwa ezinomdla kakhulu amaqhekeza xa ifunyenwe kwizilwanyana okanye izinto silhouettes. Kwaye kwenzeka ukuba ummandla onke amanani eyenziwe nguye ebe yembutho sokuqala.