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Indlela yokufumana kwirediyasi isangqa: ukunceda abafundi
Indlela yokufumana embindini wesangqa? Lo mbuzo usoloko kubalulekile ukuba abafundi abafunda planimetry. Ngezantsi sijonga eminye imizekelo yendlela uyakwazi ukumelana msebenzi.
Kuxhomekeka kwirediyasi iimeko umsebenzi isangqa, unako ukufumana indlela.
Formula 1: R = L / 2π, apho A - na la manani achazwe apha, yaye π - rhoqo lingana 3.141 ...
Ifomula 2: R = √ (S / π), apho S - sisixa kwindawo kwisangqa.
Ifomula 3: R = D / 2 apho D - na ke sangqa kwisangqa, ngamanye ubude kwicandelo leyo, edlula embindini mzobo kanga iingongoma ezimbini kakhulu bebekwe ngokwahlukeneyo omnye komnye.
Indlela yokufumana embindini le circumcircle
Okokuqala makhe ukuchaza ixesha ngokwayo. Ojikeleyo esibizwa ngokuba ezichazwe xa kumayelana zonke eziphezulu polygon. Kufuneka kuqatshelwe ukuba isangqa kungachazwa babalelwa yepholigoni, ogama amacala nee-engile alinganayo nenye ezinjalo, oko kukuthi, ngeenxa unxantathu alinganayo, isikwere, irhombus, njl ilungelo Ukusombulula le ngxaki kuyimfuneko ukufumana kwibala buyimilo, wafa esandleni sakhe kunye ndawo. Ngoko ke, bexhobile, nomlawuli, ikhampasi, isibali, kunye nencwadi ngenkxola.
Indlela yokufumana embindini wesangqa, ukuba ichazwa malunga unxantathu
Formula 1: R = (A * B * B) / 4S, apho A, B, C, - ubude macala unxantathu, kunye S - kwindawo yayo.
Ifomula 2: R = A / isono, apho A - ubude elinye icala mzobo, size isono - ixabiso ebalwe i sine ye icala engile phaya.
Embindini wesangqa ochazwe ehlabathini unxantathu ekunene-engile egqithe.
Formula 1: R = B / 2, apho B - hypotenuse.
Ifomula 2: R = M * B, apho B - hypotenuse, kunye M - udibaniso olwenziwe noko.
Indlela yokufumana kwirediyasi isangqa xa kuchazwa ngeenxa yipolygon
Ifomula: R = A / (2 * isono (360 / (2 * n))), apho A - ubude elinye icala mzobo, kwaye n - Inani lamacala kulo mzobo zejometri.
Indlela yokufumana embindini le incircle
Le Isangqa sibhalwe kuthiwa xa usebenza macala onke polygon. Nantsi imizekelo embalwa.
Formula 1: R = S / (P / 2) apho - S kunye R - kwingingqi kunye kujikelezo mzobo ngokulandelelana.
Ifomula 2: R = (P / 2 - A) * kubatshaba- (a / 2), apho P - kujikelezo A - ubude omnye amaqela, yaye - malunga nganeno ekujikeni.
Indlela yokufumana embindini wesangqa, ukuba ubhalwe unxantathu ilungelo
Formula 1:
Embindini wesangqa eya ubhalwe rhomb
A Isangqa ke abhaliwe nayiphi irhombus yinto alinganayo kunye scalene.
Formula 1: R = 2 * H, apho H - ukuphakama shape yemigca.
Ifomula 2: R = S / (A * 2), apho S - yi ariya irhombus, kwaye A - icala ubude bayo.
Ifomula 3: R = √ ((S * isono A) / 4), apho S - yi ariya irhombus, kwaye A isono - engile sine yayiyazi loo mzobo zejometri.
Ifomula 4: R = V * T / (√ (V² + G²) apho B kunye T - ubude ke idayagonali lo mzobo zejometri.
Ifomula 5: R = B * isono (A / 2), apho - ke idiagonal le irhombus, kwaye A - ke engile kwi eziphezulu ukuba ukudibanisa idiagonal.
Embindini wesangqa eya ubhalwe unxantathu
Kwimeko ukuba ngengxaki banikwa ubude asemacaleni mzobo, okokuqala ukubala kujikelezo nxantathu (U), yaye emva koko isiqingatha-iperimitha (n):
P = A + B + C, apho A, B, - ubude emacaleni mzobo yemigca.
n = n / 2.
Formula 1: R = √ ((p-A) * (n-D) * (n-B) / n).
Ke ukuba, esazi onke amaqela efanayo ezintathu, uya kunikwa okungakumbi yaye ummandla mzobo, uyakwazi ukubala uluhlu efunekayo ngolu hlobo.
Ifomula 2: R = S * 2 (A + B + C)
Ifomula 3: R = S / f = S / (A + B + C) / 2), apho - n - kuba nani semiperimeter yemigca.
Ifomula 4: R = (n - k) * kubatshaba- (A / 2), apho n - na semiperimeter unxantathu A - enye emacaleni aso, kwaye kubatshaba- (A / 2) - kodwa azikweli phezulu nesiqingatha eli cala engile esahlukileyo.
A ngezantsi indlela ngasentla ziya kufumana embindini wesangqa okubhaliweyo unxantathu alinganayo.
Ifomula 5: R = A * √3 / 6.
Embindini wesangqa okubhaliweyo unxantathu ilungelo
Ukuba ingxaki banikwe ubude imilenze kunye hypotenuse, ngoko embindini wesangqa ebhalwe njengoko ithathelwa ingqalelo.
Formula 1: R = (A + B-C) / 2, apho A no-B - imilenze, C - hypotenuse.
Xa kunjalo, ukuba ngaba umlenze ezimbini kuphela, lixesha ukukhumbula ukuba theorem kaPythagoras ukufumana hypotenuse kwaye usebenzise indlela ngasentla.
C = √ (A² + B²).
Embindini wesangqa ubhalwe kwindawo kawo-
Yenza isangqa apho ubhalwe ngendlela isikwere, yahlula yonke emacaleni aso 4 kanye isiqingatha amanqaku tangency.
Formula 1: R = A / 2, apho A - ubude ecaleni isikwere.
Ifomula 2: R = S / (P / 2), apho S kunye F - kwingingqi kunye yomjikelezo isikwere, ngokulandelelana.
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